The continuous slab shown in the figure, of span length L=5. 00 m and of thickness h=160 mm, is subjected to covering load g_{e}=1.0 kN/m^{2} and live load q=5.0 kN/m^{2}. Concrete class C50/60. Calculate the shear forces and bending moments envelopes for the three slabs, in ultimate limit state.
The design dead load for each slab is g_{d}=1.00·5.0=5.0 kN/m and the total design load is p_{d}=γ_{g}·g+γ_{q}·q=1.35·5.0+1.50·5.0=14.25 kN/m.
Manual calculations: I=(b·h^{3})/12=(1.0·0.16^{3})/12=341·10^{-6} m^{4}
Modulus of elasticity for concrete C50/60 is equal to E=37.3 GPa.
E·I=37.3·10^{9}N/m^{2}·341·10^{-6}m^{4}=12.719·10^{6} N·m^{2}
For I_{10}=I_{12}=I_{23}=I_{c}, stiffness factors k distribution indices υ are:
Due to frame symmetry: και