Concrete quantity take-off (es-ES)

The structural frame
The construction (es-ES)
The reinforcement I (es-ES)
The reinforcement II (es-ES)
Quantity/Cost estimation (es-ES)
Detailing drawings (es-ES)
Tomo A´ - Introducción

Wind and Seismic Forces > (es-ES)
Structural model and Analysis (es-ES)
Modelling slabs (es-ES)
Slabs (es-ES)
Seismic behavour of frames (es-ES)
Appendix A (es-ES)
Appendix B (es-ES)
Appendix C (es-ES)
Appendix D (es-ES)
Tomo B´ - Introducción

Materials (es-ES)
To be continued > (es-ES)
Tomo C´ - Introducción

A simple building with ground floor and basement

<project: Estimation10>

The building that will be used to calculate the quantities and cost estimation is shown at the figure on the right.
It consists of a ground floor and a basement (with one shear wall) while its foundation consists of spread footings tied by connecting beams as well as one strip foundation. The following paragraphs present the detailed quantity estimate of materials such as concrete, formworks, spacers, reinforcements, the reinforcement schedules’ optimization as well as the total quantity and cost estimate of the structural frame.

Concrete quantity estimation of ground floor

Beams – Slabs

S1: 4,40 x 5,00 x 0,18                                                                   =  3,96

(2)     b1,b2: 2 x [(5,00-2 x 0,40) x 0,30 x 0,32]                              =  0,81

(3)    C1,2,3,4 (τμήμα κόμβου): 4 x (0,40 x 0,40 x 0,32)              =  0,20

Total                                                                                             =  4,97 m3

Columns

(4)      C1,2,3,4: 4 x (0,40 x 0,40 x 2,50)                                           = 1,60 m3

Concrete quantity estimation of basement

Beams – Slabs

   S1: 4,40 x 5,00 x 0,18                                                                         =  3,96

(2)  b1,b2: 2 x [(5,00-2 x 0,40) x 0,25 x 0,32]                                      =  0,67

(3)   b3,sw5: 2 x [(4,40-2 x 0,40) x 0,25 x 0,32]                                  =  0,58

(4)   C1,2,3,4 (τμήμα κόμβου): 4 x (0,40 x 0,32)                                =  0,20

Total                                                                                                 =  5,41 m3

Columns

(5)   C1,2,3,4: 4 x (0,40 x 0,40 x 2,50)                                             = 1,60 m3

(6)    SW5: 3,60 x 0,25 x 2,50                                                            =  2,25

Total                                                                                             =  3,85 m3

Concrete quantity estimation of foundation

   Footings f3,4,5:

2 x (1,00 x 1,00 x 0,50) +3,00 x 0,85 x 0,50                                      = 2,275

(2)   CB1,2:

2 x (3,60 x 0,30 x 0,60) + (2 x 0,30 x 0,10 x 0,30) +

+ 2 x (0,30 x 0,30 x 0,30)                                                                      = 1,368

(3)   SF: 4,40 x 1,00 x 0,30 + 4,40 x 0,30 x 0,30                                        = 1,716

(4)  Columns (additional volume due to foundation depth equal to

0,60 m, compared to the footings’ depth which is 0,50m):

4 x (0,40 x 0,40 x 0,10) + 3,60 x 0,25 x 0,10                                      = 0,154

(2 x 0,10 x 0,10 x 0,20 = 0,004)

Sum                                                                                                        =  5,51 m3